PAPER / ARXIV:2609.10788
Jakob Steininger , Sergey Yurkevich
RESUMO
We prove that the Nieuwland number of the Octahedron is $3\sqrt{2}/4$. Along the way, we provide an elementary proof that Rupert's problem for the Octahedron admits no solution in which the outer projection is a hexagon.
NO MESMO MAPA